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Home » U++ Library support » ScatterDraw & ScatterCtrl » ScatterCtrl Difference in Debug and Release mode.
ScatterCtrl Difference in Debug and Release mode. [message #47664] Sat, 25 February 2017 13:51 Go to next message
deep is currently offline  deep
Messages: 169
Registered: July 2011
Location: Bangalore
Experienced Member
Hi,

When I compile my Code in "Debug" mode I get Process Shift+p menu option in popup

But when same code complied with "Release mode" then Process menu option missing.

What change is required?

Using Windows 10, MinGW

index.php?t=getfile&id=5203&private=0


Warm Regards

Deepak
Re: ScatterCtrl Difference in Debug and Release mode. [message #47667 is a reply to message #47664] Mon, 27 February 2017 09:45 Go to previous message
koldo is currently offline  koldo
Messages: 2723
Registered: August 2008
Location: Basque Country
Senior Veteran
Hello Deep

In DEBUG mode, ScatterCtrl has all menus activated to show the developer all the possibilities. However in RELEASE mode, as it is devoted to final user, just the options permitted by the developer are shown.
In this case, you can use ShowProcessDlg(); to show this dialog.
To set all dialogs you could put:
SetMouseHandling(true, true).ShowContextMenu().ShowPropertiesDlg().ShowProcessDlg().ShowButtons()


Best regards
Koldo
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