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findarg [message #37646]

Tue, 30 October 2012 13:33

mirek
Messages: 14257
Registered: November 2005

Ultimate Member

I have found I am missing some simple template function to determine that some value is in some set defined as further arguments of function, so here it goes:

findarg(4, 1, 2, 3) == -1

findarg(4, 3, 4) == 1

(defined for 2 up to 40 arguments).

Mirek

[Updated on: Wed, 31 October 2012 19:12]

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