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Splitting a single ctrl (or appearing to) [message #41690]

Fri, 10 January 2014 22:29

nixnixnix
Messages: 415
Registered: February 2007
Location: Kelowna, British Columbia

Senior Member

If I want to split one ArrayCtrl so that I can scroll one part and leave another part as is, how would I implement that please? I am thinking about how in Excel you can keep some data visible at the top while scrolling down.

Thanks for any help or suggestions.

Nick

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Re: Splitting a single ctrl (or appearing to) [message #41704 is a reply to message #41690]

Sun, 12 January 2014 10:22

deep
Messages: 278
Registered: July 2011
Location: Bangalore

Experienced Member

Actually I managed it by using two GridCtrl side by side using splitter. And on scroll I shift other control also. I wanted fixed columns.

FixedColGrid.sby.WhenAction = THISBACK ( Scroll );

void Scroll() {
int u1 = FixedColGrid.sby.Get();
ProcessGrid.sby.Set ( u1 );
}

Similar thing will be possible for vertical placement of two grids
using splitter.

Hope this may use useful.

Deepak

Warm Regards

Deepak

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Re: Splitting a single ctrl (or appearing to) [message #41757 is a reply to message #41704]

Fri, 17 January 2014 08:37

mirek
Messages: 14271
Registered: November 2005

Ultimate Member

deep wrote on Sun, 12 January 2014 04:22

Actually I managed it by using two GridCtrl side by side using splitter. And on scroll I shift other control also. I wanted fixed columns.

The last I needed that for ArrayCtrl, I did the same.

The keys is to use WhenScroll and WhenData callbacks to synchronize, something like

ArrayCtrl left, right;
left.WhenScroll = left.WhenSel = THISBACK(LeftToRight);
right.WhenScroll = right.WhenSel = THISBACK(RightToLeft);

void MyApp::LeftToRight()
{
   right.SetCursor(left.GetCursor());
   right.ScrollTo(left.GetScroll());
}

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Re: Splitting a single ctrl (or appearing to) [message #41760 is a reply to message #41757]

Fri, 17 January 2014 17:23

nixnixnix
Messages: 415
Registered: February 2007
Location: Kelowna, British Columbia

Senior Member

Thanks.

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