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reference solved: [message #58126] |
Mon, 21 February 2022 08:58 |
reign_of_terror
Messages: 6 Registered: October 2021
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Promising Member |
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Value v = 3;
Ref r=v;
Ref y = r;
Cout() << &v << "\n";
Cout()<< &y.Get<Value>()<<" :foo"<<"\n";
Cout() << y.GetValue();
Cout() << "\n";
Hi all-
If I use the code like this it returns the same memory address
for v and y.
Thanks, reign_of_terror
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