Overview
Examples
Screenshots
Comparisons
Applications
Download
Documentation
Tutorials
Bazaar
Status & Roadmap
FAQ
Authors & License
Forums
Funding Ultimate++
Search on this site
Search in forums












SourceForge.net Logo
Home » U++ TheIDE » U++ TheIDE: Layout (Forms) Designer » Direct generate implement file from .lay file
Direct generate implement file from .lay file [message #26262] Mon, 19 April 2010 17:46
ktj9 is currently offline  ktj9
Messages: 17
Registered: April 2010
Promising Member
The designer is neat. However, when I tried to use code navigation, such as context go to, to understand the codes, the .lay file becomes a pain of understanding, since it requires constant mind set switching. The preprocessor uses lay.h to generate implementation, which wraps macros and templates, two scary things together. Maybe, it is just because I am not familiar with .lay concept, or it is just because I am not comfortable switching reading .lay and c++ sources. Should pure c++ implementation from .lay be helpful? Works for me...
So I implement the generator (see below). Wish it will be helpful for some others feel the similar way. And thanks to the neat design of UPP, theIDE and lay file structure, they make these all simple... Smile

void LayDes::GenCppRepresentation()
{
	if (!IsNull(fileerror))
		return;
	String cppfilename(filename);
	cppfilename.Cat(".h");
	String ret;
	for (int i = 0; i< layout.GetCount(); ++i) {
		layout[i].SetCharset(charset);
		ret << layout[i].GenCppRepresentation() << "\r\n";
	}
	
	if (!SaveChangedFileFinish(cppfilename, ret))
		return;
}

String LayoutData::GenCppRepresentation()
{
	String out;
	out << "struct " << name << "__layid{};\r\n";
	out << "template<class T>\r\n"
			"struct With" << name << " : public T, public " << name << "__layid {\r\n"
			"\tstatic UPP::Size GetLayoutSize() {\r\n"
			"\treturn UPP::Ctrl::LayoutZoom("	<< size.cx << ", " << size.cy << ");\r\n"
			"\t}\r\n";
	for (int i=0; i< item.GetCount(); ++i) {
		if (!item[i].isUntyped())
			out << "\t" << item[i].classname() << " " << item[i].var(i) << ";\r\n";
	}
	out << "};\r\n";
	out << "template <class L, class D>\r\n"
			"void InitLayout(UPP::Ctrl& parent, L& layout, D& uts, " << name << "__layid&) {\r\n"
			"\tparent.LayoutId(\"" << name << "\");\r\n";
	for (int i=0; i< item.GetCount(); ++i) {
		if (item[i].isUntyped()) {
			out << "\tuts." << item[i].var(i) << "." << item[i].param() << ";";
			out << "\tuts." << item[i].var(i) << ".LayoutId(\"" << item[i].var(i) << "\");";
			out << "\tparent.Add(uts." << item[i].var(i) << ");\r\n";
		} else {
			out << "\tlayout." << item[i].var(i) << "." << item[i].param() << ";";
			out << "\tlayout." << item[i].var(i) << ".LayoutId(\"" << item[i].var(i) << "\");";
			out << "\tparent.Add(layout." << item[i].var(i) << ");\r\n";
		}
	}
	out << "};\r\n";
	return out;
}

bool LayoutItem::isUntyped() const
{
	return type.IsEmpty();
}

String	LayoutItem::var(int i) const
{
	String s = variable.IsEmpty() ? Format("dv___%d", i) : variable;
	return s;
}

String LayoutItem::param() const
{
	return SaveProperties();
}


To hook them into IDE, add following in LayDes::EditBar
	bar.Add(islayout, AK_GenCPPRep, LayImg::GenCPP(), THISBACK(GenCppRepresentation));

where LayImg::GenCPP is a home-made image in LayImg.
Add following to laydes.key file
KEY(GenCPPRep, "Generate CPP Representation", K_ALT_G)



Previous Topic: All controls available in layout designer
Next Topic: operator ambiguous
Goto Forum:
  


Current Time: Thu Apr 25 14:44:28 CEST 2019

Total time taken to generate the page: 0.00644 seconds