U++ framework: U++ Esc Interpreter, Esc Macros and templates

Home » Extra libraries, Code snippets, applications etc. » U++ Esc Interpreter, Esc Macros and templates » ESC and the path of Package

Show: Today's Messages :: Polls :: Message Navigator
E-mail to friend

ESC and the path of Package [message #12919]

Wed, 28 November 2007 17:27

scorpionfirevn
Messages: 5
Registered: November 2007

Promising Member

hi,
i want to write a codeformat.usc by using astyle program and the Script is like:

macro "Code Format":"Code Format" Alt+F{
filetype1 = "*.h ";
filetype2 = "*.cpp ";

cmd = "astyle --style=ansi ";

cmd<<filetype1;
.Execute(cmd);
}
i really want to put this file in common directory but it work not.
how can i get th path of the source path(source package)?

ex: astyle --style=ansi /home/abc/upp/package1/*.h

i've take a look ESC language but there is not any functions like what i want.
Any ideas
Thanks a lot
Tuan

Report message to a moderator