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Re: What Type to give a Layout as parameter? [message #34370 is a reply to message #34369]

Fri, 18 November 2011 22:15

mirek
Messages: 14267
Registered: November 2005

Ultimate Member

Wolfgang wrote on Fri, 18 November 2011 14:08

Me again... I've tried to find a way to to give a layout as a parameter to a method. But I cant find how to do it..

I have this .h

...
class Urlaub : public WithurlaubLayout<TopWindow> {
	public:
		typedef Urlaub CLASSNAME;
		Urlaub();
		WithloginLayout<ParentCtrl> loginLayout;
		WithlogoutLayout<ParentCtrl> logoutLayout;
	private:
		bool rmTab( ???? );

and in the main.cpp I have

...
Urlaub::rmTab( ???? tabLayout)
{
  int pos;
  pos = tab.Find(tabLayout);
...
}

But I dont know what type I have to use for the ???? parts...
Upp::Ctrl dont works cause of error C2248: 'Upp::Ctrl::Ctrl' : cannot access private member declared in class 'Upp::Ctrl'

Any solutions?

Well, this happens to be really unusual request...

There is a little known way how to do this: String Ctrl::GetLayoutId() returns the layout name (or element name).

Quote:

Background:
I want to create a method to check if a Tab with Layout X exists and if it does, remove it.

[/quote]

Much easier is to just remove it based on instance:

void TabCtrl::Remove(Ctrl& slave);

Mirek

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