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Re: Formatting text with percent sign [message #49898 is a reply to message #49897]

Fri, 01 June 2018 08:43

Tom1
Messages: 1305
Registered: March 2007

Ultimate Contributor

Hi,

Yes I can confirm that the standard %% works correctly with Format(). Just as I suspected after being waked up by Oblivion, my use of printf() to output the result from Format() to console caused the issue in the first place:

	Cout() << Format("%.1f %%\r\n",12.3); // yes this works: 12.3 %
	printf(~Format("%.1f %%%%\r\n",12.3)); // and this works: 12.3 %

The documentation this morning looks correct.

Thanks to both of you.

Best regards,

Tom

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[Message index]

		Formatting text with percent sign By: Tom1 on Tue, 29 May 2018 13:35
		Re: Formatting text with percent sign By: Tom1 on Wed, 30 May 2018 12:07
		Re: Formatting text with percent sign By: Klugier on Wed, 30 May 2018 15:11
		Re: Formatting text with percent sign By: Tom1 on Thu, 31 May 2018 18:48
		Re: Formatting text with percent sign By: Klugier on Thu, 31 May 2018 19:15
		Re: Formatting text with percent sign By: Oblivion on Thu, 31 May 2018 19:53
		Re: Formatting text with percent sign By: Tom1 on Thu, 31 May 2018 21:05
		Re: Formatting text with percent sign By: Klugier on Thu, 31 May 2018 22:15
		Re: Formatting text with percent sign By: Tom1 on Fri, 01 June 2018 08:43

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