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ScatterCtrl Difference in Debug and Release mode. [message #47664]

Sat, 25 February 2017 13:51

deep
Messages: 266
Registered: July 2011
Location: Bangalore

Experienced Member

Hi,

When I compile my Code in "Debug" mode I get Process Shift+p menu option in popup

But when same code complied with "Release mode" then Process menu option missing.

What change is required?

Using Windows 10, MinGW

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Warm Regards

Deepak

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Re: ScatterCtrl Difference in Debug and Release mode. [message #47667 is a reply to message #47664]

Mon, 27 February 2017 09:45

koldo
Messages: 3432
Registered: August 2008

Senior Veteran

Hello Deep

In DEBUG mode, ScatterCtrl has all menus activated to show the developer all the possibilities. However in RELEASE mode, as it is devoted to final user, just the options permitted by the developer are shown.
In this case, you can use ShowProcessDlg(); to show this dialog.
To set all dialogs you could put:

SetMouseHandling(true, true).ShowContextMenu().ShowPropertiesDlg().ShowProcessDlg().ShowButtons()

Best regards
Iñaki

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