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vsprintf() doesn't support "%I64u" format in Win32 platform? [message #14404]

Mon, 25 February 2008 16:03

HenryXin is currently offline

HenryXin
Messages: 10
Registered: February 2008

Promising Member

I log the 64bit data as following format:
SysPrintf("[%I64u,%I64u,%I64u,%s]\n", 0x12345, 0xabcdef, 0x0000, "Starting");
call this function.
SysPrintf(const char *format, ...)
{
va_list ap;
va_start(ap, format);
vsprintf(internal_buffer, format, ap);
va_end(ap);
//console_window.DisplayLine(internal_buffer);
}
But the string I get is wrong..
Call
SysPrintf("[%x,%x,%x,%s]\n", 0x12345, 0xabcdef, 0x0000, "Starting");
the result is OK.
Does stdlib not support "%I64u" format?

Best Regards
Henry

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[Message index]

		vsprintf() doesn't support "%I64u" format in Win32 platform? By: HenryXin on Mon, 25 February 2008 16:03
		Re: vsprintf() doesn't support "%I64u" format in Win32 platform? By: HenryXin on Wed, 27 February 2008 06:04

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