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Method to Open a New Layout Window [message #1414]

Fri, 03 March 2006 01:52

Justin
Messages: 57
Registered: March 2006
Location: Orange County California

Member

Hey everyone,

I am new at U++ in addition to being fairly new at C++. I have written some Win32 API applications using straight C before, but nothing fancy. I am trying to Open a layout window that was created by pressing a button. What method would I use to display the 'modify' layout after pressing the OK button on the 'ExampleLayout' layout?

Thanks in advance.

Justin

***header file*******

#ifndef _Example_Example_h
#define _Example_Example_h

#include <CtrlLib/CtrlLib.h>

#define LAYOUTFILE <Example/Example.lay>
#include <CtrlCore/lay.h>



class Example : public WithExampleLayout<TopWindow> {
public:
	Withmodify<ParentCtrl> modify;
	typedef Example CLASSNAME;
	Example();
	void Compute();
};

#endif

***cpp File**********

#include "Example.h"


void Example::Compute()
{
	
	/*
	I want this code to open another layout window
	*/
	
	
}


Example::Example()
{
	CtrlLayout(*this, "Window title");
	btnOK <<= THISBACK(Compute);
	
}

GUI_APP_MAIN
{
	Example().Run();
}

***Layout File*******

LAYOUT(ExampleLayout, 404, 276)
	ITEM(Button, btnOK, SetLabel(t_("&OK")).LeftPosZ(84, 180).TopPosZ(92, 104))
END_LAYOUT



LAYOUT(modify, 512, 316)
        ITEM(Button, btnNew, SetLabel(t_("&OK")).LeftPosZ(84, 180).TopPosZ(92, 104))
END_LAYOUT

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